probability distribution exercises and solutions

22 2 2 2 2 22 There is a 16.5 % chance of making exactly 5 shots. 3. Should I buy insurance? © Copyright 2006 - 2020 ExamSolutions - Maths Made Easy, Exam Questions - Normal distribution, finding a probability, Edexcel S1 Statistics June 2014 Q7(a) : ExamSolutions Maths Revision - youtube Video, Edexcel S1 Statistics June 2014 Q7(b) : ExamSolutions Maths Revision - youtube Video, Edexcel S1 Statistics June 2014 Q7(c) : ExamSolutions Maths Revision - youtube Video, Finding the mean in a Normal Distribution : Statistics S1 Edexcel June 2013 Q6(a) ExamSolutions - youtube Video, Normal distribution probability : Statistics S1 Edexcel June 2013 Q6(b) : ExamSolutions - youtube Video, Finding Standard Deviation from a Normal Distribution : S1 Edexcel June 2013 Q6(c) : ExamSolutions - youtube Video, Normal Distribution : S1 Edexcel January 2013 Q4(a) : ExamSolutions Statistics Revision - youtube Video, Normal Distribution : S1 Edexcel January 2013 Q4(b) : ExamSolutions Statistics Revision - youtube Video, Edexcel S1 Statistics January 2013 Q4(c) : ExamSolutions Maths Revision - youtube Video, Histogram : S1 Edexcel January 2013 Q5(a) : ExamSolutions Statistics Revision - youtube Video, Estimating a Median by Linear Interpolation | Edexcel S1 January 2013 Q5(b) | ExamSolutions - youtube Video, Mean and Standard Deviation : S1 Edexcel January 2013 Q5(c) : ExamSolutions Statistics Revision - youtube Video, Skewness : S1 Edexcel January 2013 Q5(d) : ExamSolutions Statistics Revision - youtube Video, Normal distribution : S1 Edexcel January 2013 Q5(e)(f) : ExamSolutions Statistics Revision - youtube Video, Normal Distribution : S1 Edexcel June 2012 Q6(a) : ExamSolutions Maths Videos - youtube Video, Normal Distribution : S1 Edexcel June 2012 Q6(b) : ExamSolutions Maths Videos - youtube Video, Normal Distribution - Finding a mean : S1 Edexcel June 2012 Q6(c) : ExamSolutions Maths Videos - youtube Video, Edexcel Statistics S1 January 2012 Q7a : ExamSolutions - youtube Video, Edexcel Statistics S1 January 2012 Q7b : ExamSolutions - youtube Video, Edexcel Statistics S1 January 2012 Q7c : ExamSolutions - youtube Video, Edexcel Statistics S1 June 2011 Q4a : ExamSolutions - youtube Video, Edexcel Statistics S1 June 2011 Q4b : ExamSolutions - youtube Video, Normal distribution : S1 Edexcel January 2011 Q8a : ExamSolutions Maths Tutorials - youtube Video, Inverse Normal : S1 Edexcel January 2011 Q8b : ExamSolutions Maths Tutorials - youtube Video, Normal Distribution - Finding mean and st. dev : S1 Edexcel January 2011 Q8c : ExamSolutions Maths - youtube Video, A-Level Edexcel Statistics S1 June 2010 Q7a : ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2010 Q7b : ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2010 Q7c,d : ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2010 Q7e : ExamSolutions - youtube Video, Normal Distribution : Statistics Edexcel S1 January 2010 Q7(a)(b) : ExamSolutions - youtube Video, Normal Distribution : Statistics Edexcel S1 January 2010 Q7(c) : ExamSolutions - youtube Video, Normal Distribution : Statistics Edexcel S1 January 2010 Q7(d) : ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2008 Q7a (Normal distribution): ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2008 Q7b (Normal distribution): ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 June 2008 Q7c (Probability tree diag): ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 January 2008 Q6a,b (Normal Distribution) : ExamSolutions - youtube Video, A-Level Edexcel Statistics S1 January 2008 Q6c (Normal Distribution) : ExamSolutions - youtube Video, A-Level Statistics Edexcel S1 June 2007 Q6a : ExamSolutions - youtube Video, A-Level Statistics Edexcel S1 June 2007 Q6b : ExamSolutions - youtube Video. Do not forget that if … where \(x\) is the result from part B. 0000002596 00000 n Part (c): Conditional probability : S2 Edexcel January 2013 Q5(c) : ExamSolutions Statistics Revision - youtube Video. View Solution. Part (a): Cumulative Distribution Function : S2 Edexcel January 2013 Q5(a) : ExamSolutions Statistics - youtube Video. Solutions to Exercises in Chapter 2 7 9. Here \(a\) and \(b\) are 1 and 1. The area of the square is 1 and the area of the circle is π/4 (since the radius is 1/2). Suppose we toss two dice. 1. 0000006514 00000 n If the players spend $150 on the hotel, find the mean and standard deviation of the total amount of money that the players spend. Part (a): Finding the mean in a Normal Distribution : Statistics S1 Edexcel June 2013 Q6(a) ExamSolutions - youtube Video. We will make a table of the probabilities for the sum of the dice. Should you buy insurance for $10? \[ C_{15,2} \, 0.25^2\, 0.75^{13} + C_{15,1}\, 0.25^1\, 0.75^{14} + C_{15,0}\, 0.25^0 \,0.75^{15} \]. … What is the probability of making fewer than 3 shots? List the members of the following sets: (a) (b) (c) (d) (e) 2. We compute the standard deviation for a probability distribution function the same way that we compute the standard deviation for a sample, except that after squaring \(x - m\), we multiply by \(P(x)\). My cards are 2 and a 6 and my wife's are 7 and 4. A continuous random variable is a variable whose possible outcomes are part of a continuous data set. 107 Exercises in Probability Theory 1. Exercise 4A 1. Use the following information to answer the next two exercises: The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard deviation of 2.1 days. There is a 24 % chance of sinking fewer than 3 shots. If each player spends about $100 per hour on black jack and $200 per hour on craps, what will be the mean and standard deviation for the amount of money that the casino wins per person? The LibreTexts libraries are Powered by MindTouch® and are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. We when we buy insurance in black jack we lose the insurance bet if the dealer does not have black jack and win twice the bet if the dealer does have black jack. If you take 15 shots, what is the probability of making exactly 5 of them. and the standard deviation is the same as part B since the coefficient is 1. Legal. Suppose you have $20 wagered and that you have a king and a 9 and the dealer has an ace. If you don’t know π you can estimate it by repeating the … H�b```f``Z"�x�����������[�� ~Tz��#�BN���6w�����c��@*$��>^�0:�e�ꐪ����+ĩe:UR���ᛴ8昊G��I�!7�k��^��T^kUŢ7CXQ(T�t��*CG��&2 0000001289 00000 n 6.2: The Standard Normal Distribution. trailer << /Size 127 /Info 114 0 R /Root 117 0 R /Prev 97636 /ID[<251cb5609a9c8357f1a3ac66bb75d18d>] >> startxref 0 %%EOF 117 0 obj << /Type /Catalog /Pages 100 0 R /Metadata 115 0 R /JT 113 0 R /PageLabels 98 0 R >> endobj 125 0 obj << /S 299 /T 390 /L 449 /Filter /FlateDecode /Length 126 0 R >> stream Hence the mean is. The possibilities are: Suppose that you buy a raffle ticket for $5. Gamblers who played both black jack and craps were studied and it was found that the average amount of black playing per weekend was 7 hours with a standard deviation of 3 hours. Suppose that each time you take a free throw shot, you have a 25% chance of making it. We have \( n = 15 \), \( r = 5\), \(p = 0.25 \), and \(q = 0.75\), \[ C_{15,5}\, 0.25^5 \,0.75^{10} = 0.165 \]. What is the mean and standard deviation for the total amount of gaming? For more information contact us at info@libretexts.org or check out our status page at https://status.libretexts.org. 0000001095 00000 n

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